2x^2+37x+8=0

Solution for 2x^2+37x+8=0 equation:

2x^2+37x+8=0

a = 2; b = 37; c = +8;
Δ = b2-4ac
Δ = 372-4·2·8
Δ = 1305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1305}=\sqrt{9*145}=\sqrt{9}*\sqrt{145}=3\sqrt{145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-3\sqrt{145}}{2*2}=\frac{-37-3\sqrt{145}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+3\sqrt{145}}{2*2}=\frac{-37+3\sqrt{145}}{4}
$